NLM1

How to do this in ground frame , without pseudo force
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16 Replies
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@Gyro Gearloose
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lmaodedXD
lmaodedXD7mo ago
pure ground frame ke liye consider the net acceleration caused only by immediate forces, i think tum bade block aur B ke beech mein normal nahi laga rahe
lmaodedXD
lmaodedXD7mo ago
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lmaodedXD
lmaodedXD7mo ago
isi cheez ki better understnding ke liye ye wala try karna
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hardcoreisdead
hardcoreisdeadOP7mo ago
the ans is 14mg tho wait i got it F=7ma a=F/7m T= m.a=m.g substitute a am not getting the ans to this tension in string comes out to be 240 right
lmaodedXD
lmaodedXD7mo ago
T= 2mg na in third step and yes T is coming 240
hardcoreisdead
hardcoreisdeadOP7mo ago
Yep
hardcoreisdead
hardcoreisdeadOP7mo ago
Will this be the fbd of 10kg block Ab is accn of block and Ap is accn due to pseudo force
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lmaodedXD
lmaodedXD7mo ago
block ke 2 accelerations nahi ho sakte, you can say that m*Ap is the pseudo force and net acc wrt bada block is leftwards or in ground frame you can say that a-2 (rightwards) is the net acc of block wrt ground
hardcoreisdead
hardcoreisdeadOP7mo ago
thats what i am kinda implying
Spartan
Spartan7mo ago
Ismein poore system ko 1 block lele pehle as the system remains in contact Block a aur b ko kholde net as horizontal with pseudo forces and tension hojaayega
hardcoreisdead
hardcoreisdeadOP7mo ago
Pseudo force nahi lagana that's the whole point , nvm tho yeh ho gya Yeh wala bata de
BANE
BANE7mo ago
3360 hoga right @hardcoreisdead @lmaodedXD ? tension string mein 240N aajayegi m1 is moving with 20N towards left so total applied force towards left is 260N which is the pseduo force = ma a=26 mass of horizontal frame = 120 kg M and m2 would have internal force by normal 12026 = F-T F = 12026 + 240 = 120 *28 3360
hardcoreisdead
hardcoreisdeadOP7mo ago
+solved @BANE @lmaodedXD
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