C
C#4mo ago
sardar97

How to Bind typeparam with property in Blazor?

i have a generic Component which is a generic form and i get properties in a generic way then i pass them to the components depend on the property type like (int,string...etc). Inside some entity i have relation and class. for example i have Blog entity in Post entity. then i want to get the Blog and bind it to my anoteher generic components which name is SQEntityPicker. and this picker require some parameter and typeparam the only problem i have is typeparam TValue , I must write it like this "@typeparam TValue where TValue : class, new()" in my case. Then it would must to pass TValue whenever i use SQEntityPicker. As i explained i get properties in a generic way then i don’t know how to pass the property to the typeparam and bind it. i share all of the codes for both components.
8 Replies
SleepWellPupper
SleepWellPupper4mo ago
Can you use $paste please? It's more friendly for mobile users (me) :)
MODiX
MODiX4mo ago
If your code is too long, you can post to https://paste.mod.gg/, save, and copy the link into chat for others to see your shared code!
SleepWellPupper
SleepWellPupper4mo ago
Generally you may supply the generic type argument to generic components by using the type parameter name like a component parameter, but instead of supplying to it a value you supply a type. sometimes the compiler is able to infer type arguments based on other parameters you supply
sardar97
sardar974mo ago
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sardar97
sardar974mo ago
that is right the compiler will do that if i just define TValue like this (@typeparam TValue) but if i define it this way (@typeparam TValue where TValue : class, new()) then the compiler will not infer that and it would be must to define TValue from the parent component when the child used. And in my case i have to define TValue this way (@typeparam TValue where TValue : class, new())
SleepWellPupper
SleepWellPupper4mo ago
Well it looks to me like your @bindProperty is available in a weakly typed manner only; you're using reflection to obtain information about it etc. etc. You can't go from weakly typed to I suddenly have the type information available at compile time without is conversions, casts etc. None of which is robust in my opinion.
sardar97
sardar974mo ago
well. what should i do there? could give an example code?
SleepWellPupper
SleepWellPupper4mo ago
You can try making your SQEntityPicker weakly typed, so as to accept an object instead of TValue. Your constraints class, new() don't give you much more information than the object type itself
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