M
Modular•7mo ago
staycia930

I do not know why the output is like this!

I ran two almost identical programmes but the output changed. But I don't understand why the output changes. I would like to know. First Program 
def greet(name: String):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)
def greet(name: String):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)
First output 
Hello, Mojo!
Hello, Mojo!
Seccond Program 
def greet(name):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)
def greet(name):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)
Seccond output 
'Hello, Mojo!
'Hello, Mojo!
Using my environment ・MacOS ・Python3.12 ・Poetry ・mojo 24.4.0 (2cb57382)
1 Reply
Brad Larson
Brad Larson•7mo ago
In the first, you've provided a type to the name argument (String), whereas in the second you've left name untyped. In the latter case, Mojo will default to object for the argument in a def function. This causes the slightly different printing behavior between the two types.

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