Modular•5mo ago

I do not know why the output is like this!

I ran two almost identical programmes but the output changed. But I don't understand why the output changes. I would like to know. First Program

def greet(name: String):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)

def greet(name: String):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)

First output

Hello, Mojo!

Hello, Mojo!

Seccond Program

def greet(name):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)

def greet(name):
    name = "Hello, " + name + "!"
    print(name)

fn main():
    var name = "Mojo"
    try:
        greet(name)
    except e:
        print("Error: " , e)

Seccond output

'Hello, Mojo!

'Hello, Mojo!

Using my environment ・MacOS ・Python3.12 ・Poetry ・mojo 24.4.0 (2cb57382)

1 Reply

Brad Larson•5mo ago

In the first, you've provided a type to the name argument (String), whereas in the second you've left name untyped. In the latter case, Mojo will default to object for the argument in a def function. This causes the slightly different printing behavior between the two types.

Gaming

Programming

I do not know why the output is like this!