Needed help with explanation!

Hey, what's the probable explanation to this. I started strong, then literally got lost in translation. Jokes apart , ig the first one is the answer
the question ofc
10 Replies
iTeachChem Helper
@Dexter
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Max_34561
Max_345617mo ago
You can always check the node Actually wait
Cakey Bot
Cakey Bot7mo ago
iteachchem
Transcription requested by TempestUknow
This is from IAT, right, I think I've solved this question live on the, whatchamacallit, but anyway, yeah, what Max said is absolutely right, you can check the nodes. Now this, and there's a small thing, right, I'll mention that later, it's got one node, which means that psi should be equal to zero, except r equal to zero, because it's not zero at r equal to zero right now, you can see that, right, psi is not equal to zero there. So that's, these are two separate points, okay, so with that, you eliminate option C because at r equal to zero, psi is equal to zero, anything else gets eliminated, no, okay, and also option B gets eliminated because it's not possible, it does not have any nodes, option B does not have nodes. You're right, A is the only one that has one node, because 2 minus r by A naught will be equal to zero. You don't consider the e power minus r by A naught where r tends to infinity, you don't consider that to be a node. And lastly, the option D would be, would have two nodes, whatever, there's a function with two nodes, and also no node at r equal to zero. So you're right, first one is the answer.
PeterGriffinItis
PeterGriffinItisOP7mo ago
Thanks a lot sir 🙏❤
Cakey Bot
Cakey Bot7mo ago
iteachchem
Transcription requested by NotKrish
So how it works here is that you can mark a post sold. So who has helped you right? So you go plus salt and add the name of the user who helps you there's a space between both of those things.
iTeachChem
iTeachChem7mo ago
+fsolved
iTeachChem Helper
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