galvanometer div

Why are we taking the full division , ans comes when we take full division but galvanometer has that-ve 0 +ve deflection so shouldn't we take only half the divisions. Ans is 1
No description
No description
9 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Comrade Rock Astley
The range includes both sides, since it is considered that a negative value in a galvanometer can also be meaningful Not sure if that's the convention across jee questions but that's how you'd explain this option
Gamertug
GamertugOP8mo ago
Wait , why would the range include both sides it makes no sense. Right side of zero and left side of zero give same value . How will that implement in an voltmeter
Comrade Rock Astley
It means that the potential difference is on the opposite side so current is flowing the other way round
Gamertug
GamertugOP8mo ago
Ye still the magnitude must be same , the question is asking for range of 0 to xV , so shouldn't we take only half the divisions
Comrade Rock Astley
The idea is that even though the magnitude is the same, the actual value (and the direction of the needle) is different and we understand the data from it or it can be converted into a different reading later on (eg: instead of labelling the galvanometer from -xV to +xV you can label it from 0 to +2xV)
Gamertug
GamertugOP8mo ago
+solved @Comrade Rock Astley
iTeachChem Helper
Post locked and archived successfully!
Archived by
<@700658749416669194> (700658749416669194)
Time
<t:1719503495:R>
Solved by
<@769492044837552139> (769492044837552139)

Did you find this page helpful?