Kysely•5mo ago

What am I not understanding about ColumnType?

(Apologize if this is very nooby I am new to kysely as of today) Used kysely-codegen and it spit out something like the following:

export type Int8 = ColumnType<
  string,
  bigint | number | string,
  bigint | number | string
>;

export interface UserTable {
  ...
  phoneOneCountryId: Generated<Int8>;
 ...
}

export type Int8 = ColumnType<
  string,
  bigint | number | string,
  bigint | number | string
>;

export interface UserTable {
  ...
  phoneOneCountryId: Generated<Int8>;
 ...
}

(Maybe it shouldn't be Generated? My current thought is code-gen marks that because the column has a default value? I'm struggling to find in kysely docs clear right/wrong here.) Which I then wrap:

export type NewUser = Insertable<UserTable>;

export type NewUser = Insertable<UserTable>;

However when I go to use like so:

const testNewUser: NewUser = {
      ...
      phoneOneCountryId: 20,
      ...
    };

const testNewUser: NewUser = {
      ...
      phoneOneCountryId: 20,
      ...
    };

I get compilation error:

Type 'number' is not assignable to type 'Int8'.ts(2322)

Type 'number' is not assignable to type 'Int8'.ts(2322)

---------------- If I understand how codegen set up Int8 correctly with ColumnType then it passed

bigint | number | string,

bigint | number | string,

as the InsertType (middle arg). So I wouldn't expect this to error - what am I missing here?

Solution:

So I figured out through combing through kysely-codegen closed issues that there is a differnece between the out-of-the-box kysely Generated type and the Generated type I was removing (that I thought was extra) that gets generated with codegen. When I restored for the codegen one the compilation issue went away. For reference current codegen type: ```export type Generated<T> = T extends ColumnType<infer S, infer I, infer U> ? ColumnType<S, I | undefined, U>...

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1 Reply

Solution

WhyDoThis•5mo ago

export type Generated<T> = T extends ColumnType<infer S, infer I, infer U>
  ? ColumnType<S, I | undefined, U>
  : ColumnType<T, T | undefined, T>;

export type Generated<T> = T extends ColumnType<infer S, infer I, infer U>
  ? ColumnType<S, I | undefined, U>
  : ColumnType<T, T | undefined, T>;

I dismissed the bot response before so I can't see how to mark this solved now.

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What am I not understanding about ColumnType?