27 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.well seems correct.....
Yes the answers marked are correct if that's what you want to ask @hardcoreisdead
I want their proof
you do understand the c option right?
if you understand the c option then simply the b option is a(vector ) multiplied by the unit vector to get the component of a(vector) in the direction of v(vector)
Nah that's the whole problem
Speed is only changed by tangential acceleration @hardcoreisdead
While centripetal acc only changes the direction of motion
@hardcoreisdead.
Is my diag correct
V2-v1 signify accn here
try to bring V2 vector and v1 vector tail to tail, then draw the vector thru head of v1 towards v2, that would represent the "amount" by which the vector v1 was shifted to get v2, in other words, a (after dividing by time ofcourse).
also not it would only be the average accelartion......
Is this relevant???
Imma be honest I don't get it
Anyone ?
It's not too important, it's up to you whether you want to learn it
about the question.. u got a soln?
hmm
If you exert a force on a body in a particular direction, there is acceleration in the same direction
This acceleration can be represented by a vector, and any vector can be resolved, or "split" along any set of axes
for example, we take the case of a body in a circular path (like in the question)
(very rough diagram)
Let the green lines be the axes, let the white curve denote some circular path, let the square be the body on that path
That body is fixed on the path, hence the velocity is along the path
Now, this acceleration can be "split" along the axes
here a1 is parallel to the horizontal axis (say x-axis) and a2 is parallel to the vertical (y) axis
The point is that whether you apply acceleration a, or acceleration a1 and a2 together, the result on the body is the same
and the proof of that lies in trigonometry (can you prove it?)
Now, similarly you can take any other system of axes and resolve the vector along them, so for convenience I will take one axis (x) along the direction of v, and another (y) perpendicular to it
like this
And similarly you can resolve it like this
Now, a2 causes a change in velocity perpendicular to the path
But we know the object cannot move that way because it is fixed to the circular path somehow, hence a2 has no effect
However, a1 has no such issues and causes a change in velocity along the direction of the path, where the object is free to move
Hence, the component that is parallel to the velocity/path is the only one that affects motion
Have I answered your question? Does this help, do you need any clarification?
omg tysm for such a detailed explanation. earlier i was considering normal accn only and not the net of tangential and normal. thanxx. ill be closing the thread now
+solved @Comrade Rock Astley
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