electro chem
On the online soln of this ques they took E0 for Zn as it is. Shouldn't we multiply it by -ve first since rn is opp? Q 104
19 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Can you share that solution? From what you are saying, yes zn is at anode so that should happen
In This E0 is 1.53 , only possible of they took Ezn negative, the ans also matches
this looks correct to me
How shouldn't E0 be = 0.77 - 0.76 = 0.01
what is the formula you are using? can you write that down ek baar?
see the data in the q. reduction potentials are given of both species
Srp of cell = Srp cathode - Srp anode
Standard reducn pt
@iTeachChem is this right?
Bilkul. Ab substitute karo :D
Negative of negative is positive na.
In question E0 is neg then we mult it by neg cuz rxn is opp now it is positive. Then we subtract it so E0 = 0.77 - 0.76 = 0.01
i did not follow what is the 'then we subtract part'
'reaction is opposite'
is same as reversing sign
Yes
so you have done this once already
either you reverse the sign OR you subtract
doing both does not work :D
Ooooooo
reversing sign, makes it SOP
Ok got it
so the eqn would change to SRP cathode + SOP anode.
Ye
+solved @iTeachChem
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