I
iTeachChem•8mo ago
Aguilar

circuit symmetry

Everytime i ask my teacher why the current divides in a symmetrical circuit in such a way that both the symmetrical sides becomes equipotential, he doesn't tell me the real reason why, only says if there's symmetry, it happens .. can anyone explain
18 Replies
iTeachChem Helper
iTeachChem Helper•8mo ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helper•8mo ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
myst1cboomer
myst1cboomer•8mo ago
like dis one?
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Gamertug
Gamertug•8mo ago
Are u asking why a current divides symmetrically in symmetrical circuits? If yes the look at this In this circuit A divides into 2 symmetrical routes, now notice both routes are exactly same , same resistance, same everything (sometimes end point might not be same but u will understand ) so both routes are basically same. So why would current prefer one or the other it will go equally in both
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Aguilar
AguilarOP•8mo ago
@Gamertug @myst1cboomer yes u guys are getting the idea.... Take this case, how does the current know that it has to distribute into 2i and i in those directions, why do they always wanna make the whole circuit equipotential?
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Gamertug
Gamertug•8mo ago
Wdym by eqpt what pts are eqpt
Aguilar
AguilarOP•8mo ago
Take the first 2 resistors for example(this happens to all resistors
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Aguilar
AguilarOP•8mo ago
Both parts becomes equipotential (V-6i) But why does current divide in such a way so it becomes equipotential? That's the doubt i have And i wanna know the real reason, not symmetry
Gamertug
Gamertug•8mo ago
I never heard of that concept abt ep pt so I cant tell
Aguilar
AguilarOP•8mo ago
Alright no worries, thanks anyways
Gamertug
Gamertug•8mo ago
Np
Deleted User
Deleted User•8mo ago
ok so if you are talking "how" the current checks the paths, before actually travelling em down......its a deeper territory i would say......but for now i can provide the info that the "energy" isnt actually even travelling through the wires! the actual electromagnetic energy to the source point is travelling through space at speed of light (C), so it "checks" the conditions way ahead before the actual electrons in its influence start travelling down the road.... i would request you to check poynting vectors (funny name ik 😄 ). @Gamertug @Aguilar like imagine you put a lot of students in a crowd of boat, that floating in the stream. these are your electrons. but who is guiding your boat? the stream flow ofcourse. now imagine the stream bifurcates into 2 somewhere ahead of you, and one of the bifurcation is larger,(say, providing less restriction to flow), so what would you expect? a higher number of boats to be going thru the larger bifurcation (while it is true that not all would go there, some amount of boats are still expected to move through the smaller stream). so it is actually the driving element that actually guides your boats, or electrons if you say. this has been my understanding.
Aguilar
AguilarOP•8mo ago
That's the best way to put it Thanks i get the idea now The energy ur talking about is the electric field around the circuit wires right?
Deleted User
Deleted User•8mo ago
Aguilar
AguilarOP•8mo ago
I've watched this lol, that's why i know energy is contained in elec fields
Deleted User
Deleted User•8mo ago
nice man!
Aguilar
AguilarOP•8mo ago
+solved @Deleted User
iTeachChem Helper
iTeachChem Helper•8mo ago
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