Modular•6mo ago

Benchmarking code that raises

I am trying to use benchmark to time numpy code. However, numpy raises and it appears that benchmark.run cannot handle a function that raises. I am not a python programmer, so I am not familiar with the exception syntax. Is there a way to wrap numpy code such that the surrounding function does not raise?

2 Replies

Jack Clayton•6mo ago

Yeah you can wrap it in try/except:

from python import Python
from benchmark import run


fn main():
    fn bench():
        try:
            Python.evaluate("x**2")
        except:
            pass

    var res = run[bench]().mean("ns")
    print(res)

from python import Python
from benchmark import run


fn main():
    fn bench():
        try:
            Python.evaluate("x**2")
        except:
            pass

    var res = run[bench]().mean("ns")
    print(res)

tkeittOP•6mo ago

I tried that and it did not work. I'll give it another go.

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Benchmarking code that raises