circular motion
Question number 10 Multi correct question.Managed the A and B part. Not able to get C
32 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.$$R = [1+(\frac{dy}{dx})^2]^{3/2}$$
Keshav
above the ground lvl if-
$$R<h_{max}$$
Keshav
Keshav
Yep I got this answer
btw here a is the component of accelration perpendicular to velocity
But option c is an answer too. Pls explain that
B and C are quite similar
its some wording shit
In c it's "may be above the ground" and in b it is "is above the ground". Dk how that makes a diff in answer
I am confused as well
What I am thinking is this
2nd question. Multi correct , same problem. Got c and d but somehow b is an answer too
How is circular motion possible if radial accn is zero thus bringing no change in dirn
its is possible
but only if its zero for fraction of a second
for exmple if I have a string and I project it with a certian velocity (in vertical plane) then at the highest point, radial acceleration is about 0
$$v= \sqrt{5gl}$$
this is that required speed
its quite standard so dw
Keshav
Ohh, we've been taught horizontal circular motion only.
...
yeah
this maybe above the ground thing
includes both the scenarios
of R being greater than H and less than H
but the thing is, it can happen at any angle
expect 0
Weird. I'll ask my teacher ig
is the answer key correct
cuz I searched a brainly answer and he missed it too
but again I can't rely on a brainly answer
Ig
This is from fiitjee kinematics package
@lmaodedXD give it a try bud, till then I will think @hardcoreisdead ask your teacher and think obviously
Will do. Thanx for the effort
shayad misprint hai
tan^2 theta> 2 aaya matlab
tan theta> root 2, or than theta< - root 2
Haan possible
@hardcoreisdead
any updates?
One guy did say this . I have class on Saturday so I'll ask the
hey! was this sorted?
Yeah I asked my phy teacher
cool!
+solved @Keshav @lmaodedXD
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