current
If two wires of same length and area have resistivity p1 and p2 qre joined in parallel the net resisitivity is? The answer is 2p1p2/p1+p2 im getting p1p2/p1+p2 where im wrong?
15 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.p_net = (R_net)(2A)/l
Area double?
Yup. Parallel
In series the length of the resistance gets doubled im clear with this but in parallel how does the area gets doubled?🤔
Only one hand free atm so can't draw, but imagine the wires have cross section as square. Put them in parallel. Rectangular cross section of double area
Ahh..i see i was just thinking of it as a line we draw
Did you understand?
Yes i did
Then close the thread mate
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