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@Gyro Gearloose
Note for OP
+solved @user1 @user2...
to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.bro do it by considering equal part of it opp to it and it has electric field vector in dirn of 45 degree
the resultant is equal to sigma/4epsilonnot
E*root(2)=sigma/4epsilonnot
Bhai electric field vector in dirn of 45° kese ?
ek min bhai josaa krne de
Josaa matlab ?
aata hoon
i would say try to imagine it like superposition of a half ring that has been rotated through only 1 quarter....so divide it into differential rings, and vectorily add up their individual E fields....
solid angle should work too.....if through a solid angle of 2pi we have sigma over 4 e0
then for a solid angle of a quarter hemisphere.....u can do the unitary math...
Please solve the whole
Flux se try kar sakta, ig?

@Say_miracle_shadow
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Thank you
@myst1cboomer 👍
Close kr do
Kese hota h
+ solved then mention me
+ solved @myst1cboomer
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