I
iTeachChem8mo ago
Takt

mole concept

How do we start solving this? Which equation is to be followed out of the two? The answer is given as 6L
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Keshav
Keshav8mo ago
is it something to do with limiting reagent cuz with 3l of H2 only 1 L of N2 would react for the second reaction and for first, 3L of N2 will react
Takt
TaktOP8mo ago
Will the reaction that takes place depend on the ratios in which we take the reactants?or other conditions?
Keshav
Keshav8mo ago
yeah it depends on the amount of h2 you take its in the qs but there's nothing concrete given so, I am speculating limiting reagent
iTeachChem
iTeachChem8mo ago
i solved a similar q on the doubts with masses https://discord.com/channels/1226379612238385242/1245773731683635321 ye aap hi ne poocha tha :) remember
Keshav
Keshav8mo ago
@iTeachChem why won't the second reaction take place? It can still react with 1L of N2 @Takt yeah the first reaction will take place and form 3L of product so we are left with 2L of N2 therefore, contraction will be simply 5+3 -2 = 6L
iTeachChem
iTeachChem8mo ago
it will :) na both will take place i feel the process will be similar to this @Keshav
Keshav
Keshav8mo ago
but in the solution I checked online they only cared about the first reaction
iTeachChem
iTeachChem8mo ago
interesting so it is like the Xe and F2 reactions depending on the ratio of Xe and F2 you get XeF2, XeF4 and XeF6 Noted!
Keshav
Keshav8mo ago
but its still weird They just said, "depending upon the supply of H2'
iTeachChem
iTeachChem8mo ago
haan ioc is weird
Takt
TaktOP8mo ago
Yesss, thank you sir Also As the products are not gaseous, we can't determine the volume, right? Wouldn't that depend on the density of the liquid formed?
iTeachChem
iTeachChem8mo ago
well, volume of gas reduces since gases are being consumed that is the angle we should be looking at
Keshav
Keshav8mo ago
xD By contraction, they mean intial and final volumes of gases we had in this case, we had 8L of gas intially and after the reaction we were left with 2L of N2 so 8-2L of contraction = 6L
Takt
TaktOP8mo ago
Got it, thank you so much +solved @iTeachChem @Keshav
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