projectile motion
A projectile is thrown with a speed u at an angle theta to an inclined plane of inclination beta. Find the angle theta at which the projectile is thrown at such that it strikes the inclined plane horizontally.
18 Replies
@Gyro Gearloose
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I deduced that velocity is horizontal when the projectile is at max height for normal projectile motion
Therefore is considered it a case of normal projectile motion with an angle of theta+beta
Found ymax and x which is R/2
Used eqn of trajectory and now getting theta+beta=45
This is striking normally
I've done this part
wdym by striking horizontally then?
Pls point out my error
I solved with another method but I need the answer in tan
i got the same value
I got $$\theta=arctan(\frac{sin2\beta}{2})$$
Opt
@hardcoreisdead
This is from physics galaxy
I believe this is wrong
Instead of 4 there should be 2 rest same
yea i found an online solution which has 2
the book most probably has a printing error
+solved @Bedstorm @Opt
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