Atomic Structure
My approach:
No. of orbitals = n² = 25
No. of electrons = 2n² = 50
If there are 3 spin quantum numbers that would mean 3 electrons in one orbital
No. of electrons = 3n² = 75
Dunno what to do after this
36 Replies
@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Ans is given as (B) 27
Sir I did use the 3n² formula at the end of my message
Does that make sense?
Sir process samajh nahi aaya
Humne 75 electrons nikalne ke baad kya kiya
sir i think he is using this logic
woh nikalne ki zaroorat nahi hai
Acha
awesome notes buddy 🙂 thanks for sharing
open up ptable.com
How are we counting the elements?
check the periodic table
Wait I have it
there, 5th period has these orbitals:
5s, 4d, 5p (NO f electrons)
Yeah got it
1 + 5 + 3
orbitals
each orbital has 3 electrons
3 x 9 = 27
that is it 🙂
Acha
So this is the number of electrons
Which is the same as number of elements right 😄
for a neutral atom, Z = no. of electrons.
Yup
that is it!
i.e. Number of electrons = number of elements
But isn't the atomic number = number of electrons
yes
there are 27 electrons in the 5th period
so 27 elements 🙂
usse pehle bhi honge (which is what you were doin by counting total electrons btw)
the reason this does not work
is because this is number of stuff in the 4th and 5th shell, n = 4 or n = 5
here we are talking about the periodic table
two diff things
order of filling electrons is from aufbaus rule
khair do from first principles, that will work. jo upar explain kiya
Yeah I'll ponder upon that
this is basically how many electrons are there in the 5th shell or n = 5, which is completley different from the 5th period (open the periodic table to see what i mean). that was the main deviation in the starting.
we have to focus on the 5th period which has
5s, 4d, 5p electrons ONLY. (note how there is no 5d or 5f or 5g, this is important)
n2 for n = 5, ie 25 would be for 5s, 5p, 5d, 5f, 5g (1 + 3 + 5 + 7 + 9 = 25)
so that approach is off here.
Got it
5th period only has 5s, 4d and 5p electrons
If you are wondering what is 5g, l values are from 0 to n-1,
so for n = 5, these are the values l can take.
l = 0 (s), 1 (p), 2 (d), 3 (f), 4 (g)
so be careful where to use formulae in general 🙂
Yeah those just go on and on.
Time to use the brain and stop using formulas
I'll keep this thread open till tomorrow if I have any more doubts.
Sir I don't get this part
Yes sir. 27 electrons kaise aaye wo samajh aagaya. But 27 elements kaise hue wo nahi pata laga.
+solved @iTeachChem
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