charge is slightly displaced and released along the perpendicular bisector. the shm time period is ?
13 Replies
@Gyro Gearloose
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Send your solution pls
@koyakim0613
i cant really i gave up my phone
but i ll tell you what i did
fnet ki equation likhi hai
but then -k x ke form mein nahi aarhi
You have to assume x<<R
i did that
Accha?
yes
So if we write
We have
[2KQ/(x^2 + R^2)] * costhetha
So if we just put costhetha x/✓x2 + R2 you'll get the answer
done thanks
💀 basic trigo hi nahi aati thank you
thanks @Deleted User
Koi ni this is how u learn
+solved @Deleted User
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