I
iTeachChem•10mo ago
Gamertug

electrochemistry

Why is working condition for a cell at eqm can anyone explain?
11 Replies
iTeachChem Helper
iTeachChem Helper•10mo ago
@Dexter
iTeachChem Helper
iTeachChem Helper•10mo ago
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
iTeachChem
iTeachChem•10mo ago
you mean eq pe e = 0? have you done the derivation for nernst eqn starting from dg = dg0 + rt ln q?
Gamertug
GamertugOP•10mo ago
In my note book it's dg0 + rtln q
iTeachChem
iTeachChem•10mo ago
ah yes my b + 🙂
Gamertug
GamertugOP•10mo ago
Yes i did it
iTeachChem
iTeachChem•10mo ago
thanks for the clarification so, when q = K, dg = 0, right? and dg = nFE so E is 0 at eq
Gamertug
GamertugOP•10mo ago
Is this from eqm ch? my memory is a bit fuzzy
iTeachChem
iTeachChem•10mo ago
yea! i have done this in detail in my electrochem session, take a look. should take you 10 min probably alternatively, just read this up on chem libre texts 🙂 electrochem is like thatm need to do gaseous state, thermo and eq before it properly for it to make sense and redox!
Gamertug
GamertugOP•10mo ago
Ok Oh ok thx got it +solved @iTeachChem
iTeachChem Helper
iTeachChem Helper•10mo ago
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