Maths cengage, Inequalites
Illustration 1.25 and 1.27 third subdivision sry cant send photo, unable to.
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@Apu
Note for OP
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bruh let me type it for everyone
1.25
$$(x^2 -4)\sqrt{x^2-1}<0$$
Keshav
1.27 (iii) Find possible value of expression
$$ \frac{1}{x^2-x-1}$$
Keshav
First condition
\newline $x^2-1>0$
\newline second condtion
\newline $x^2 - 4<0$
\newline now solve and take intersection
Keshav
why tho
According to the Q, the answer should be less than 0; can't be equal to 0 (strict inequality).
Now, the expression under root cannot be negative, nor it can be equal to 0, so greater than 0.
Hence the first conditon, (x+1)(x-1) > 0
For second condition, it's very clear tht (x+2)(x-2) < 0
I hope u get my point
why cant the espression under root not be 0?
oh i get it cuz then eq= 0 sirry i understand now
+solved @Slembash
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