whats the answer?is it 0 and 1??

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36 Replies
iTeachChem
iTeachChem8mo ago
,rotate
TeXit
TeXit8mo ago
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iTeachChem Helper
@Apu
iTeachChem Helper
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Real potato
Real potato8mo ago
Either you can make inverse function by interchanging x and y or just draw the graph of f(x) and take its mirror image about y=x to get f^-1(x) from graph you can easily solve it
prodbyskie
prodbyskieOP8mo ago
Bhai i need solution😭😭
Cakey Bot
Cakey Bot8mo ago
iteachchem
Transcription requested by Aman | Jee 25
उसके लेगे you can look it up online bro this person is helping you, telling you how to make the effort Try to करो Question लिखके solution ढून हा tum को कही बहुँ रहा है This server is for you to figure things out
@Ameya²
@Ameya²8mo ago
@prodbyskie find f inverse for these 2 branches and solve for common branches for both f(x) and f-1(x). try this or the graph wala method someone told earlier. Both are equally good.
prodbyskie
prodbyskieOP8mo ago
Bhai, am facing issues in finding the common domains, Thats the reason behind me prioritising the need for a written solution Fine, i’ll share the way i solved, kindly point out my inaccuracies
Cakey Bot
Cakey Bot8mo ago
iteachchem
Transcription requested by prodbyskie
Zaroor zaroor zaroor share kariye. I try my best but I'm not a maths guy but I'm pretty sure people will help you out. And what about inaccuracies? Aap aapna method share kariye then people will be able to you know maybe can look at a better way of solving it. If you are unable to do it then for whatever reason, that's the reason for asking.
Comrade Rock Astley
For the inverse function, your range is given so from that, find the domain for each for example For f(x) = 1-x we have f^-1(x) = 1-x too In the first case the domain is x<1 here the range is f^-1(x) <1
prodbyskie
prodbyskieOP8mo ago
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prodbyskie
prodbyskieOP8mo ago
Is the solution correct?
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@Ameya²
@Ameya²8mo ago
,rotate
TeXit
TeXit8mo ago
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@Ameya²
@Ameya²8mo ago
arre whats this bot pehle msg pe reply Kia toh ye dusre ko rotate karha hai 😔
Sidd
Sidd8mo ago
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Sidd
Sidd8mo ago
,rotate
TeXit
TeXit8mo ago
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Sidd
Sidd8mo ago
@@Ameya² here
iTeachChem
iTeachChem8mo ago
Yo you good @prodbyskie ?
prodbyskie
prodbyskieOP8mo ago
Heyo I’ll wait patiently for the judgment
iTeachChem
iTeachChem8mo ago
oh what sidd says does not work? he gave an input and so did rock
prodbyskie
prodbyskieOP8mo ago
Couldn’t get it bro, wdym?
iTeachChem
iTeachChem8mo ago
this ^
Sidd
Sidd8mo ago
I didn't give an input, ameya was having trouble rotating the image so I rotated it for him/her
iTeachChem
iTeachChem8mo ago
lmao sorry my bad
prodbyskie
prodbyskieOP8mo ago
…… I very humbly want to ask about when will my doubt be resolved For the time being i’ll post my other doubt
Comrade Rock Astley
Did you try finding the domain of the inverse function in both cases?
@Ameya²
@Ameya²8mo ago
yoo you have done an elementary mistake for (2) branch of f(x) your last step: y=1±√x while x≤0 root isn't defined for x≤0 the last 3 steps are where everything went wrong also for finding inverse first try to get x as a function of y first and then take the inverse i.e x→y, y→x example: y=2x+3 2x = y-3 x=(y-3)/2 x→y, y→x: f-1(x)=y=(x-3)/2 makes stuff easy for complicated functions and you won't face domain related issues either also for 2nd branch of f(x) for your ques, y = -(x-1)² -y=(x-1)² x-1=√-y x=1+√-y y->x, x->y f-1(x)=y= 1+√-x
prodbyskie
prodbyskieOP8mo ago
Thanks a lot bro, let me analyse it
iTeachChem
iTeachChem8mo ago
+solved @@Ameya² @Comrade Rock Astley
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