mole concept (POAC)
Here is what I tried
3X + 5H2 --> XH4 + X2H6
Let molecular weight of X be m g/mol
Applied POAC for x by taking product masses as 5.628 minus x and x
Obtained an equation in x and m
3(5/m) = (x/m+4)+(2)[(5.628-x)/(2m+6)]
15/m = (x/m+4)+(11.256-2x)/(2m+6)
Also given in the question that moles are in the ratio 2:1 for the product
Thus,
2x/m+4 = (5.628-x)/(2m+6)
Solving these 2 equations gives a negative molecular weight for X
15 Replies
@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Awesome effort. btw, poac zaroori hai kya karna? i have never liked it tbh xD
lemme try
wait huhhh which q do u need help in again?
The first one, question 55
I don't like it too, it doesn't come to me naturally while solving, but I don't there's a simpler way to approach it
are you sure you wrote the right reaction?
I'm not sure, went by the question
Wait
I uploaded the wrong image
I took a photo of the correct question but the upload failed and I selected another imagine by mistake
haha
thats what i was wondering
cuz what you did was nowhere related to the q
Sorry for the inconvenience
source ?
Coaching module
Thank you sir, will check this out once I reach home
I understood it now, thank you so much
Also, I think the process for solving with POAC is the same, it's a just a fancy acronym for the fact that moles of CO2 and C is the same and conservation of the substance on both sides of the reaction
+solved @iTeachChem
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