26 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Keshav
Keshav10mo ago
,rotate
TeXit
TeXit10mo ago
No description
Keshav
Keshav10mo ago
its 50 or 60
Deleted User
Deleted UserOP10mo ago
60
hardcoreisdead
hardcoreisdead10mo ago
is it written "2 balls cross each other ?"
Deleted User
Deleted UserOP10mo ago
Yes
Deleted User
Deleted UserOP10mo ago
No description
Deleted User
Deleted UserOP10mo ago
No description
Deleted User
Deleted UserOP10mo ago
,rotate
TeXit
TeXit10mo ago
No description
Deleted User
Deleted UserOP10mo ago
Anyone ? :"))
hardcoreisdead
hardcoreisdead10mo ago
i have a approach max height by ball 1 (the one going up) is 180m achieved at t=6 at t=12 it will reach the point from where it was projected. whereas at t=12 ball 2(going down) wouldve covered 840m . now, at some time t=t, ball 2 will cover say distance S and ball 1 will cover 840+S try using this ig if some1 has a better approach pls reply
Real potato
Real potato10mo ago
Whats the answer? t=5/7 sec?
Deleted User
Deleted UserOP10mo ago
Idk Can u send the soln?
Real potato
Real potato10mo ago
No description
Real potato
Real potato10mo ago
@Deleted User
Deleted User
Deleted UserOP10mo ago
The ans would be wrong as both the bodies wont reach the point at the same time
Real potato
Real potato10mo ago
Hve u checked it by putting t=5/7? Im getting H= 40.6 something
Deleted User
Deleted UserOP10mo ago
But both bodies will have diffrent times and the difference is of 9.4 m which is pretty large
Real potato
Real potato10mo ago
Wht do you mean bh diffrent times?
Deleted User
Deleted UserOP10mo ago
OH SHIT THEY WONT IM DUMB
Real potato
Real potato10mo ago
(°_°)
Deleted User
Deleted UserOP10mo ago
I think ur right, i did the whole thing again and got 5/7, Thanks! +solved @Real potato
iTeachChem Helper
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Time
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