Trigno Limits

tex, limit x tends to 0 \frac{1-\cos\left(x\right)\sqrt{\cos\left(2x\right)}}{x^{2}}
30 Replies
iTeachChem Helper
iTeachChem Helper•8mo ago
@Apu
iTeachChem Helper
iTeachChem Helper•8mo ago
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Ansh Agarwal
Ansh AgarwalOP•8mo ago
,tex $\lim_{x\to 0} \frac{1-\cos\left(x\right)\sqrt{\cos\left(2x\right)}}{x^{2}}
iTeachChem
iTeachChem•8mo ago
yo sup. nice formatting 🙂 is this q not happening? What did you try so far?
PINGUIN
PINGUIN•8mo ago
lhopital
Ansh Agarwal
Ansh AgarwalOP•8mo ago
i tried applying the standard 1-cosx/x^2 limit can you please explain
PINGUIN
PINGUIN•8mo ago
u havent studied lhopital's rule?
Ansh Agarwal
Ansh AgarwalOP•8mo ago
i don't think so
PINGUIN
PINGUIN•8mo ago
well then w8
TeXit
TeXit•8mo ago
Ansh Agarwal Compile Error! Click the :errors: reaction for more information. (You may edit your message to recompile.)
No description
PINGUIN
PINGUIN•8mo ago
is it 0? @Ansh Agarwal
Ansh Agarwal
Ansh AgarwalOP•8mo ago
3/2
PINGUIN
PINGUIN•8mo ago
T_T how men
Ansh Agarwal
Ansh AgarwalOP•8mo ago
idk , mera bhi 0 aa rha tha , then 1/2
PINGUIN
PINGUIN•8mo ago
(1- cos x) / x obv 0 ko tend karta hai w8 lemme try lhopital
Ansh Agarwal
Ansh AgarwalOP•8mo ago
it would be a 0/0 form indeterminate
PINGUIN
PINGUIN•8mo ago
after trig manipulation it tends to 0 w8 mai lhopital se karke check karta , lemme eat dinner first
Ansh Agarwal
Ansh AgarwalOP•8mo ago
ok , thanks +solved @Ansh Agarwal
Opt
Opt•8mo ago
Uh i remember doing this. LDNE The limit doesn't exist. Nvm It was similar but different. I'm dumb. That one was with sine, not cosine. This is just 3/2
KaiZên
KaiZên•8mo ago
3/2 kahan diya hai answer? Soln mein? lim x->0 (1-cos x )/ x^2 = 1/2. Isse use karke jo root mein bachega usmein limit value put kardo. Ans phir 1/2 mujhe aa rha hai. L Hospital rule laga ke bahut hi jyada lamba ho jayega. Im confused ki hows the ans 3/2. As far as im solving, im doing it right... Did you rationalize the funtion then solve it to get 3/2?
Ansh Agarwal
Ansh AgarwalOP•8mo ago
Yup Double L hopital did the trick
KaiZên
KaiZên•8mo ago
Yeahh it will, but that is very lenghty. You can rationalize the funtion and solve as well my doubt is, what is wrong with the method in which im getting ans as 1/2?
Ansh Agarwal
Ansh AgarwalOP•8mo ago
One of mates solved it via Taylor series (Ig he was the only one who did it via l hopital) Ye yaha nahi lag payaga coz of the 2nd cos Even if you break it into 2 this won't work
KaiZên
KaiZên•8mo ago
Why? I mean I know breaking it into 2 is the reason its not working, but why cant i break it into 2?
Ansh Agarwal
Ansh AgarwalOP•8mo ago
For that you need to see how the rule was made The rule made using series expansion (the proof of which is college level maths) Which does not allow for it being broken like this
KaiZên
KaiZên•8mo ago
The taylor series expansion?
Ansh Agarwal
Ansh AgarwalOP•8mo ago
I am not sure about that tbh
KaiZên
KaiZên•8mo ago
Coool no worries, thanks tho!
iTeachChem
iTeachChem•8mo ago
+solved @KaiZên
iTeachChem Helper
iTeachChem Helper•8mo ago
Post locked and archived successfully!
Archived by
<@1035556259417571408> (1035556259417571408)
Time
<t:1718990524:R>
Solved by
<@759468963884564502> (759468963884564502)

Did you find this page helpful?