27 Replies
@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.ik ez for you all, but i can't do this . idk why
??
Not all brother
aap kre do
What do you have so far?
treat m terms as constant and evaluate the sumation of n then do the same with n
Me Abhi anpadh category me Ata hu
same
@myst1cboomer
I see summation of 2 variable, i skip 😎
chad
ca ya give sol
on vacation bruv cannot pick up the pen
try what i said
ayy putnam pyqs
real
$\sum\sum\frac{\frac{m^2\cdot n}{m^2\cdot n}}{\frac{3^{m}}{m^{}}\left(\frac{n\cdot3^m}{mn}+\frac{m\cdot3^n}{mn}\right)}$
real
then after cancelling
$\sum\sum\frac{1}{\frac{3^{m}}{m}\left(\frac{3^{m}}{m}+\frac{3^{n}}{n}\right)}$
real
real
real
real
this latex shit takes too mfing long 😠iske baad am aur an ko interchange karo
the entire summation remains the same
so S = sigma sigma 1/am(an+am) and S = sigma sigma 1/an(an+am)
add both of them, 2S
common nikalo
wapas am and an ka value dalo, uske baad basic stuff
You could also reduce it to a_n/(a_m+a_n) for an alternative approach
Not sure if that's longer than what real suggested
+solved @realize @Comrade Rock Astley
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