Can't do either of these đ„Č
How to do đ I've spent a good 30 mins of brainstorming but can't get anything
31 Replies
@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Bruh
,rotate
let (x,y)â(AĂB)â©(CĂD)
(x,y)âAĂB and (x,y)âCĂD
(xâA and yâB ) and (xâC and yâD)
(xâ A and xâC) and (yâB and yâD)
xâ A â© C and yâB â© D
(x,y)â(A â© C)Ă(B â© D)
i cant reallllllly read the question 36 too much light at the end đ
domain is the set of numbers that you can input into the function. Look at the inequality in qn 36 and you can see the domain is given to you as a mod function. |x| <= 3 means x belongs from [-3, 3]
Ok
Likewise, range is the set of numbers you get as an output of the function when you after you input the domain into it. Calculate y=|x-1| for all the values of x in the domain and all the values that you get are the range of this relation
Did you get the logic about how |x| <= 3 gives values b/w [-3,3]?
Yes because mod allows for the value inside to be both +ve or -ve cuz applying mod the outcome value is +ve anyways and since x<=3 value will lie between -3 and 3
perfect
But x is a real number we can't really compute this
x belongs to integers innit? Its given in the question.
Oh yea
Didn't see that
Also lets say a range cannot be computed, you can write it as a set of numbers. You get me?
Thanks dude
Soo if it were given that x is a real number then do we inequate mod x-1 to -3 and 3? and then find the intersections?
Inequate? You mean x-1 = 3 and x-1 = -3?
No as in <=-3 and 3 (I'm relative new to this and I'm not too familiar with the terminology like is inequate a word? Idk man I'm tired đ)
Nope. [-3,3] is the domain, which means these are the values of the variable x
Wait is this not an interval?
Thus if x belongs to real, you will just find y=|x-1| for the max and min value of x i.e 3 and -3 in this case
Ohhh and all values of y lie in between
It is an interval which defines the set of values that only x can take
Yeee okk
Yeahhh spot on.
I'm starting to get it now
Also inequate aint a term. No worries tho đ
Noice I'm sure a bunch more questions and I'll be good at this shit
đ„Čđ
Happy to help :))
+solved @KaiZĂȘn
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