22 Replies
@Gyro Gearloose
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.in q9, there will be 2 components
just do dv= -e.dr and then put the limits of the coordinates
q 13, distance will be 10 sin 30 and E= delta v/delta r so 40-20/10sin 30
calculate it and the answer will come
Bruhaakash module🤣
@Gamertug
9 th ka 1st and 13 ka 4th answer h
Now what
I got the ans
answer A hai kya?
q9
Yes how
see along the field, the point that is further (towards the arrows), uska field will be lower, understand the logic, electric field is from + to -, the farther it is from the +ve side the lower the potential gets as potential= Kq/r [lmfao actually we measure this in terms of work done but this is my absurd logic]
and V=-Edr ofc so to find the difference in magnitude, find the difference in position along the direction of field
i've taken that distance to be x here
look q.13 ke liye:
An equipotential surface ek aisi surface hoti hai jiske har point pe potential is same ie there is either no electric field along the surface ( EF can only be perpendicular as it isn't along the surface) or electric field is 0.
so we have some equipotential surfaces in q.13
EF shall be perpendicular to these surfaces or in this case the EF lines would be perpendicular to the lines shown on the graph
And EF moves from higher potential to lower potential
i hope this makes my statement more clear and you can probably figure out the EF vector
Awesome inputs everyone!
we good with this @Gamertug ?
I have completed that question
Ik the logic but idk how to calculate
dekho maine x kaise calculate kiya
(cheap application of pythagoras XD)
Cant even understand
Wait what is x
difference in position along the direction of field
+solved @lmaodedXD
Post locked and archived successfully!
Archived by
<@1035556259417571408> (1035556259417571408)
Time
<t:1716258018:R>
Solved by
<@1034231350141653132> (1034231350141653132)
+solved @@Ameya²
Channel is already marked 'Solved'.