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@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.[-1/3]=-1...
Same would follow till
[-1/3-2/3]... Closely speaking
[-1/3-66/100]
From [-1/3-67/100] it'd be -2
[-{100+201}/300]=[-301/300]=-2
So.. number of ones =(66-0)+1=67
And number of twos =(99-67)+1= 33
So 33*2+67= -133
Q 53...
yo @Gamertug please share an attempt so we can figure out what you are thinking and help you better
i cant think of anything , the only thing i tried was to get modulus on LHS and open it and solve but it did not work
before that, it forms a quadratic eqn right?
2 of them considering the mod
(i dunno what i am talking about, a guess from what i recall 😄 may be completely off, sending this until someone who knows math responds!)
wait how
take 2^x as y so you get a quadratic in y, right?
and you take two cases, y-1 <0 and y-1 >0
in case 1 you have to write it as -2^x + 1 (cos mod hai)
in case 2 use as is
so you get two quadratics in y 🙂
Oh
🙂 were you able to figure it out from here?
1 root honge
Mene class m solve krha hua hai
yep this is the method
Solve the quadratic in each case, and see if your solutions match the case
Ye only 1 root will be right
Arn't all 4 roots real numbers am I missing something?
2 power x cant be negative right.
You are calculating y there at the end btw.
Oohh
Ye I got the ans thx
+solved @iTeachChem
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