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@Gyro Gearloose
Note for OP
+solved @user
to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Why not this?
They have asked the component of A which is perpendicular to vector B, not which is perpendicular to B cos theta.
Thus you will take the component of A namely Acos(theta) for vector B. There is no need to take B cos(theta) as that is not going to help.
But a cos theta and b to same direction me hai in diagram
That is just to show ki itna distance ka projection nikalna hai... projection of vect A on b = Acos(theta)
Matlab? Me samjha nhi
You mean ki a cos theta vector b ke perpendicular nhi hai blki uske parallel hai ya pair Thoda angle bna hai?
no that's not b cos theta 💀 what you've labeled as b cos theta is actually A sin theta
Yes mb I found that before
So how is a cos theta perpendicular to b vector?
it is not, A cos theta is along (parallel to, or can say, kind of superimposes)b vector
So when the question is asking about perpendicular component why we taking this?
accha perpendicular pucha hai
toh A sin theta lo, wo perpendicular to b vector hoga
sorry maine dekha nahi
But solution me to a cos theta Liya Hai 💀
misprint in question ig
Sure?
haan haan
right
Projection perpendicular hi hota ?
nahi, projection matlab uska component ALONG the other vector
Ohh
wording dekho na bhai, "on" likha hai, matlab along that line
Bro I have another small doubt about solving modules
i'm no teacher main dropper hu mujhse advices mat lo
Allen Ki exercise ke q ke sath code Likha hota Hai usse solution kese find kru?
main allen ka nahi
Phir kiska Hai bro?
fiitjee
Ok bro Thanks a lot 👍✅
+solved @lmaodedXD
allen ki app pe har ch ke almost har question ka soln hai that's why the code is there so you can find the soln for that q with the code
bhai dusre account se type karna hai
Vector B lo. Usko plot kardo. Vector A lo, aur usse plot karo, just like how the diagram is given.
Abhi vector A jo hai, voh B ke upar ek shadow jaisa maar rha hai, am i right?
abhi A ke do components banao
Abhi agar aap dekhoge, A costheta ek dum B ke upar baith rha hai, while A sin(theta), B se perpendicular hai.
Projection of A on B matlab, A ka koi component B ke upar shadow jaise baithna chahiye.
Hope you are able to understand now...
Thanks a lot bro doubt clear ho gya
So it means that question me print error Hai?(Becos vaha pr perpendicular pucha Hai)
Yes, misprint hai.
Thanks a lot bro 🤓
Make a right angled triangle with the magnitudes of the components you got, then find the hypotenuse. Then use sin theta or cos theta formula to find the angle.
Anytime bro, wishing you the best!
Didnt understand
Bro I think the question is incomplete
Threads done sir, Incredibler posted their own doubt instead of makin a new thread, so yeah.
Yep your right... vector A nahi diya hua hai...
the full qn: https://brainly.in/question/4587642
+solved @KaiZên
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