14 Replies
@Gyro Gearloose
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.it signifies the magnitude of the resultant vector
Magnitude of vecotr
But use modulus bhi legate ig
And vo sqrt kaha se agya?
we generally right
$|\vec{A}|$ as simply $A$ for convenience
Keshav
Oh
And sqrt kaha se Aya?
I think magnitude formula?
Yeah obviously
Pythagoras Theorem
If $\vec{A} and \vec{B}$ are perpendicular, then the magnitude of resultant can be given by - $\sqrt{A^2 + b^2}$
$\sqrt{A^2+B^2}$
Keshav
Yes got it thanks bro
+solved @Keshav
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