how do I solve 11...
I kinda deduced that answer is A cuz root will always be greater than 0 and not equal to 0... But I don't understand how we can solve this like mod ka kya kare 💀
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@Apu
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It's always a good idea to split a mod piecewise
so, take the case where x is negative, and take the case where x is nonnegative
X+ mod x greater than equal to 0 ?
then you can figure it out
But x can't be -ve cuz of the root...
No it can't be equal to 0 cuz then 1/0 would be baad
Ah then 4
x + mod x shouldn't be negative
x can be
$x+|x| > 0$
\ if $x>0$ then $2x$ is our denominator
\ if $x \leq 0 $ then 0 is our denominator
Fermat's Last Theorem
So obviously $x>0$ is our solution set
Fermat's Last Theorem
Under root usually is >= 0 but here only >0 therefore x is > -|x|
Which would obviously always be -ve so the domain would be (0, inf.)
Hmmmmmm ok
Thanks
How many aakash students are there in this server lol i am in aakash too. Write +solved @ whoever solved it to archive this
Aakash students are all over disc
Fr
+solved @Fermat's Last Theorem
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