basic Chemistry
How can I find the number of electrons lost or gained by an oxidising agent or reducing agent.?? Like kmno4,k2cr2o7
(I am struggling in finding equivalent weight of oxidant and reductant)
16 Replies
@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.Dude just check the central atom. The oxidation state of the central atom is the number of electrons lost/gained (mostly)
Sir, A petition to remove the slow mode. Its excruciating to wait for the timer to run out while typing an explanation.
+1
Thanks bro but can U give me an example?
KMnO4 in acidic medium. Manganese's oxidation state goes from +7 to +2. That makes it 5 electrons change.
Isn't there a shortcut I got a test tomorrow of a chapter(basics of Chem) and I only need to calculate equivalent weight of substances
I am a fresher so is it necessary to study a new chapter for calculating equivalent weight(I got more things to do)
Sir I am a fresher I neeed to prepare basics of Chem chapter and it's big(I need a shortcut If there is for tomorrow's test)
calculating oxidation number is easy
substances like oxygen and potassium in this example are mostly there in 1 state only. At the stage where you are at just adding OS and summing up to the charge should be more than enough.
Sorry bro Mujhe smj nhi Aya what you said
Thanks so much bro
Youre welcome
Hey please mark things as solved once you are sorted
(On all your threads :D) type +solved followed by the persons id who helped you.
Ok sir
+solved @Joe Biden
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