4 Replies
@Gyro Gearloose
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.From vector addition we know that
P+R=Q(vectorially)
Now S= P+ bR (vectorially)
Now R can be again written Q-P (obv vectorially)
So S=P+(b)(Q-P)
= P(1-b) + bQ (obv vectorially again)
Proof that
S= P+ bR
_
-> S = P + A (say) now A can be shown by magnitude=b|R| and direction= R i.e. R (cap)=A(cap)
Hence A(vector) can be said to be b(R)(vector)
hey you good with this?