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@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.how do i start with these kinds of questions?
i think this question is from PNC
basically if 3 variables are given u fix one variable and find pairs for other two
then the variable u fixed , give it other values and try to find pairs
bro solution mei i don't think they used pnc
In 2a^2 + b^2 = 8c+7, you can use modulo of 8
We know 8c+7 mod 8 is 7
yeah...
use a = 8k+0/1/2...7 and b = 8l+0/1/2...7
Let's say a=8k+n1 and b=8l+n2
a^2 mod 8 is just n1^2 mod 8
Similarly b^2 mod 8 is just n2^2 mod 8
After that you'll have to check each combination to find which one gives 7
ohhh
and how would you do this? like putting in all possible remainders in the question?
Yes, except you'll only need odd values of n2
Since 2n1^2 is even
oh okay, got the answer 👍 tysm
+solved @Comrade Rock Astley
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