Physics, Motion in a straight line Class 11.
Q: A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2 m/s^2
. He reaches the ground with a speed of 3ms. At what height, did he bail out ?
Ans I got: I got V = Root of 980, however i dont understand why acceleration (here:2m/s^2) is considered negative
although it says deceleration it still goes in the direction of displacement and velocity
8 Replies
Pls someone help.
@Gyro Gearloose
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.but direction of velocity and displacement is opp to the direction of acceleration
how..?
sorry im studying on my own so brain a little slow. pls excuse if i dont understand quicker than u expect me to.
wait u say deceleration means opposite to that of the direction of velocity and displacement?
Look the parachutist is going in the downward direction
Taking the convention for down to be +ve
We know that 2m/s² [net acceleration] of the parachute upwards is occurring...
[Basically this acceleration is the net acceleration from the parachute's drag force{here considered constant} and (force) acceleration due to gravity]
OH OK I GOT IT, THANKSSS
+solved @Sam @myst1cboomer
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