plz solve

Chemistry question 5 and maths question 2
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iTeachChem Helper
@Dexter @Apu
iTeachChem Helper
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Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
iTeachChem
iTeachChem9mo ago
hey buddy, please make separate threads for different qs also an attempt, a working of what your thoughts are, that helps a lot, share that as well,
!Nimay¡
!Nimay¡9mo ago
Think about ionic potential Charge/radius factor More ionic potential more polarizing power of cation more it steals electron density from the ligand and the ligand comes closer and the H in OH gains more delta positive and hence becomes easier to remove
Sukritya
SukrityaOP9mo ago
Answer not matching with this method...I have tried it...the answer given is A...
!Nimay¡
!Nimay¡9mo ago
Weird [Al(H2O)6]3+ should be the strongest
Sukritya
SukrityaOP9mo ago
Bro but how will you know the radius??...you need to memorize it kya?
!Nimay¡
!Nimay¡9mo ago
Al3+ is bound to be smaller than Fe3+ bruv Fe bhot baad mein aata hai
Sukritya
SukrityaOP9mo ago
But Zeff and sheilding effects are also there na...
!Nimay¡
!Nimay¡9mo ago
Decreases along the period increases down the group
Sukritya
SukrityaOP9mo ago
For elements not for ions of that elements...
iTeachChem
iTeachChem9mo ago
Salt analysis padha hai kya? They all precipitate as hydroxides. Does this help? Ksp value increases down the group hydroxides - basically these ions.
Sukritya
SukrityaOP9mo ago
@iTeachChem still didn't understood why the answer is A
Aditya
Aditya9mo ago
The rate law for a reaction between the substances A and B is given by Rate = k[A]^n[B]^m. On doubling the conc. of A and halving the conc. of B, the ratio of the new rate to the earlier rate of the reaction will be as:
Comrade Rock Astley
For maths Q2, split 3 into 4-1 and 5 into 4+1, expand by binomial theorem
!Nimay¡
!Nimay¡9mo ago
2^n/2^m = 2^(n-m)
myst1cboomer
myst1cboomer9mo ago
250 will be the answer probably for maths one although chem one is out of my bounds
Sukritya
SukrityaOP9mo ago
500 ans given...
Aditya
Aditya9mo ago
A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm^-3, then the number of atoms present in 256g of the crystal is N×10^24. The value of N is:
Sukritya
SukrityaOP9mo ago
+solved @iTeachChem
iTeachChem Helper
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