Maths limits
Seeking little assistance with this function. Will it be discontinuous at x-->2, x--> sqrt(5) or x-->5?
Ik its very obvious...
My question is can I eliminate sin(pi.x) by multiplying and dividing with (pi.x) theen solve the limit? Or should i just substitute it in the sin function?
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@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.sin x / x = 1 when x tends to zero
from what i infered from your method , you are trying to use this somehow? for x--> 2 x--> sqrt 5 ?
Yeah this method only
can we multiply and divide by (pi.x) so that the sin gets eliminated and then we sub the limit?
sin wont get elemenated
sinx/x is one when limit of x tends to ZERO
Oh yes shoot what the fuck i made such a dumb mistake mb bro, sorry for wasting your time
+solved @Weirdo
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