I
iTeachChem•10mo ago
Xyphoes

PnC

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26 Replies
iTeachChem Helper
iTeachChem Helper•10mo ago
@Apu
iTeachChem Helper
iTeachChem Helper•10mo ago
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Xyphoes
XyphoesOP•10mo ago
Honestly no idea where to even start with this In the solution, They took Tr as coeff of x^r in expansion of (e^x + e^-x)/2 They said this with no explanation whatsoever I can only think of generating functions, as they usually have terms like these, but other than that I have no idea
Sam
Sam•9mo ago
Another reason to hate aakaas solutions😔
Xyphoes
XyphoesOP•9mo ago
video solution bhi bakwaas hai banda bas word to word bole jaa rha hai, shayad se usko bhi samajh nai aaya hoga
Linarp
Linarp•9mo ago
yes aakash ☕
Dragon Slayer
Dragon Slayer•9mo ago
bro aakash solutions are the worst lambe se lambe question ko bhi 5 line maximum mein khatam kar dete
Deleted User
Deleted User•9mo ago
+1
r0h4n_
r0h4n_•9mo ago
akash probably worst coaching
iTeachChem
iTeachChem•9mo ago
@Xyphoes did you figure this out? And keep discussions to the point please, the focus of the doubts section is to help each other with the thought process needed to figure out the solution. Let us keep this constructive.
Xyphoes
XyphoesOP•9mo ago
Nope :/ I gave up on this cause there's no point in doing it now with such little time left
iTeachChem
iTeachChem•9mo ago
ek baar lets try @Apu any inputs?
iTeachChem
iTeachChem•9mo ago
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iTeachChem
iTeachChem•9mo ago
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iTeachChem
iTeachChem•9mo ago
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iTeachChem
iTeachChem•9mo ago
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iTeachChem
iTeachChem•9mo ago
(disclaimer, tried with gpt 4o free wala, just copy pasted there and asked for solution, does this help? @Xyphoes )
Xyphoes
XyphoesOP•9mo ago
Nope, just gibberish XD
iTeachChem
iTeachChem•9mo ago
aaaaaaaaa itna confidently bs SAD!
Xyphoes
XyphoesOP•9mo ago
just classic chat gpt
Fermat's Last Theorem
Fermat's Last Theorem•9mo ago
Requires extra theory - exponential generating function
Comrade Rock Astley
Comrade Rock Astley•9mo ago
right
TeXit
TeXit•9mo ago
Comrade Rock Astley
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Comrade Rock Astley
Comrade Rock Astley•9mo ago
I think the way to do this in the exam hall would be to observe that the solution involves 2^k (because of the options), and observe that nC0+nC1+..+nCn=2^n and work backwards from that that's...really the only quick way to figure this out @Xyphoes (ping just in case)
Xyphoes
XyphoesOP•9mo ago
Thanks, this seems atleast somewhat thinkable XD +solved @Comrade Rock Astley
iTeachChem Helper
iTeachChem Helper•9mo ago
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