Quadratic equations doubt
The question says that the roots are equal, so the discriminant must be zero. Using that property, I'm getting a²m² = (m² + 1)(a²-b²) but the answer is given as (m²+1)(a²-b²) = 0
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@Apu
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Are you sure about the brackets?
Oh yes that works, didnt think of it as I was trying to prove am=0
Thank you and sorry for the stupid doubt
[REDACTED]
It was (m2 + 1)(a2-b2)
On the paper you forgot the brackets
Oh yes, I forgot to put brackets after writing it in the next line which is why it went wrong, thank you
Yep
The approach was correct
+solved
.+solved @ᴘɪᴄᴄʜɪ | 🎧 🎶
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