Limits
Is it a mistake in the solution when they went from step 2 to 3?
The limit formula for x^n - a^n / x-a needs the limit as x --> a right, but here they gave it as x-->0 and still used the formula
7 Replies
@Apu
Note for OP
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In the case let's say
1+3x =t
So as x->0+
t->1+
So you can say..
,tex
[t^{1/3} -1]/[t-1]
Oh yes you are right, i just clubbed 1+3x rather than assuming it as a variable. My bad. Thank you so much!
The solution is accurate
You can also just use L H'ospital rule if you want
Obv I prefer using Standard Limits cause they're really handy
+solved @Sam
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