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@Gyro Gearloose
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Comrade Rock Astley
and...since there's no change in velocity you really just have to assume net acceleration is 0
so equate mg with B^2 l^2 v/R
oh okayy got it
just one thing tho, can you have a look at my initial steps and tell whats wrong. because when i differentiated Φ=Bl^2 i got ε=2Blv. and in the expression for force also im getting (2 . B^2 . l^2 . v)/R
so equating it with mg gives v = 20 and i get the wrong answer but when i keep force as (B^2 . l^2 . v)/R, im getting the right answer. so where am i going wrong
Think of it as Bl x l
Width is always constant so only one term changes
When you differentiate B(l^2) you’re doing B (l x dl/dt) + B(dl/dt x l)
Here one of those terms is 0 because the width never changes
oh okay, thanks !!
+solved @Comrade Rock Astley
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