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@Dexter
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.This is what I did, but apparently carbon monoxide is released during the acylation, and instead we get alkylation
isnt C triple bond O supposed to be highly stable? Would there be enough activation energy to enable the release of carbon monoxide?
I got this right in test I got the product you formed as X, AlCl3 as Y and HCl as acid Z
I actually formed AlCl4- as Y in the test lol
dono parts galat gaye par
Close
i think R galat hai
butyne + hot alk KMnO4---> propanoic acid
propanoic acid on electrolysis ----> ethane (free radical mechanism)
nvm just realised it is pentyne
tough luck. yea alcl4- is unstable esp when there are acidic H around.
@iTeachChem Anything on this? In the actual solution they've eliminated CO to form a benzylic carbocation
I could see how a benzylic carbocation would be stable BUT, organic, you are much better off asking the students who have already responded 🙂
@Dexter any inputs on this?/
Well I did the same, this is a special case of friedel crafts , basically whenever we can make a more stable carbonation the the acylinuim ion decomposes, I will pin an example which will help
Here tertiary butyl acylinuim decomposed and gave tertiary butyl carbonation, the similar thing happened in the question
+solved @¹¹⁷sos
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