Limits - Possible expansion qn
Im not able to understand the simplification of the second step to the final step in the solution. I asked the doubt to PW Saarthi faculty but he said the ans is wrong and needs to be 0. Im confused 💀
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@Apu
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.consider expansion for such questions
without using the cos a + cosb formula? straight up expansion?
yeah selective expansion you eliminate the terms that are eliminated and keep those which are cancelled by denominator
Didnt get what your trying to say... so I expand cos() and then (sinx)^2 in the cos expansion?
exactly not fully though only the terms which can be cancelled
Im not getting it... you mind sending a picture of your working?
are you sure ans is 1/3
i am getting 1/6
damn. Now idk thats what the option says. My doubt faculty was saying the ans might be 0
in the second sin term x^2 will get cancelled out so wee check for the next lowest power which is x^4/6
sin(x^4/12) / (x^4/12) = 1 so multiply and divide by x^4/12
this way im getting 1/6
did you get it?
i tried a method which is somewhat easier to pop in mind like applying l hospital 2 times and we get easier situration of expansion>
but i also have the explanaination of the step you didn't understand
do you understand my feelings from this step
Please excuse me, but im not good at math... can you tell me how you got that -x^4/3! term? 🥲
although i am able to understand the steps and stuff after that, which remove the second sin term effectively getting 1/6 multiplied with first term
nvm i got it, thank you for your help!
+solved @myst1cboomer @Linarp
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