I
iTeachChem10mo ago
Takt

Vector (A+B) will be perpendicular to?

I had this question in my coaching test. Shouldn't Vector (A+B) be perpendicular to A-B as A=B? As they form a rhombus and the diagonals of a rhombus are perpendicular to each other. I also drew it and am getting them to be perpendicular, for both A-B and 3A-3B. I checked the answer on Byju's and Toppr but it is also marked as A cross B there, so something must be wrong with my solution.
No description
30 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
KaiZên
KaiZên10mo ago
Firstly for any vector to be perpendicular to the other, it should lie in a different plane and have 90 degrees . In option B and C, the resultant vector lies in the same plane as A+B, thus it is not perpendicular
Priyam Alok
Priyam Alok10mo ago
So î and j are not perpendicular huh?
myst1cboomer
myst1cboomer10mo ago
but all of these is correct
Priyam Alok
Priyam Alok10mo ago
Yes
Takt
TaktOP10mo ago
Two vectors in different planes would always be perpendicular, but two vectors in the same plane could also be perpendicular when there is a right angle between them, right?
myst1cboomer
myst1cboomer10mo ago
. product seems simple enough to explain this
KaiZên
KaiZên10mo ago
Well yes, but in this case |A| = |B|, thus the only possibility of your statement wont work
Priyam Alok
Priyam Alok10mo ago
Yes you are correct...i think question has misprint and it want you to ask that which of the following is perpendicular to A and B not A+B
myst1cboomer
myst1cboomer10mo ago
but guys i think he is right for the question he got don't you agree?
Takt
TaktOP10mo ago
46% people who attempted the test marked Option A and got it right
KaiZên
KaiZên10mo ago
I get it, my bad
Priyam Alok
Priyam Alok10mo ago
NVM 🙂
Takt
TaktOP10mo ago
Taking a random case, consider two vectors with equal magnitude, vector A to be 3i+4j and vector B to be 4i+3j. (Both have a magnitude of 5 units). A+B would be equal to 7i+7j. A-B would be -1i+1j. The formula for dot product is a.b=abcosP where P is angle between a and b, so cos P = a.b/ab (a+b).(a-b)=-7+7=0 ab = (root 98)(root 2) so cos P = 0/(root 98)(root 2)=0, thus P = 90deg It's working if I take a random case, but solution videos from PW and Doubtnut insist that A is the answer
Jiya
Jiya10mo ago
in that case the question isnt clear they shouldve said perpendicular to the plane
prasadam123
prasadam12310mo ago
Is it solved? A-b is not always perpendicular to A + b For example taking a and b to be in opposite directions like one goes north and one goes south ... in this case a-b is not perpendicular to a + b @Takt
Priyam Alok
Priyam Alok10mo ago
Ya but here magnitude of both is same
prasadam123
prasadam12310mo ago
yes so they wont be perpendicular right
Titan.
Titan.10mo ago
I answered d for the same question , we both are part of the same coaching .
Priyam Alok
Priyam Alok10mo ago
Bro they will pe perpendicular just do dot product and see The dot product will be zero
Titan.
Titan.10mo ago
yes , but why is it that in most of these websites the answer is a 😭
Priyam Alok
Priyam Alok10mo ago
They might be wrong bro like meri jee mains ki shift me ek NLM ka question aaya jisme most sites ne ROD or contact point pe reaction force surface ke perpendicular nahi liya just to match the wrong answer of NTA
Priyam Alok
Priyam Alok10mo ago
No description
Takt
TaktOP10mo ago
Thanks for this, I'll ask my physics teacher next class
Priyam Alok
Priyam Alok10mo ago
Ok ask maths teacher too he may also help
Takt
TaktOP10mo ago
He said we are right about this +solved
iTeachChem Helper
You need to mention a member to mark the thread as solved. +solved @user. This will be added to their stats.
Takt
TaktOP10mo ago
+solved @Priyam Alok
iTeachChem Helper
Post locked and archived successfully!
Archived by
<@697758262186999819> (697758262186999819)
Time
<t:1713989407:R>
Solved by
<@582564114631491605> (582564114631491605)

Did you find this page helpful?