Parallel Reaction doubt ( MOLE CONCEPT )

please explain how to approach & Solve this question.

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@Dexter

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trin•10mo ago

so the reactions are CaCO3 -------> CaO + CO2 (eq-1) Na2CO3 + CO2 + H20 -------> 2NaHCO3 (eq-2) Converting the kg to g:- 21.2 * 10^-3 106 is the molecular weight of Na2CO3 No: of moles of Na2CO3= 21.2*10^3/106 = 200 mole => 1 mole of Na2CO3 reacts with 1 mole of CO2 (since the stoichiometric coefficient is same) now, since number of CO2 moles in eq 2 is 200 then number of CO2 moles in eq1 will be also 200 and since 1 mole of CaCO3 gives 1 mole of CO2, hence number of CaCO3 moles will also be 200 moles. weight of CaCO3= moles x molar mass => 200 x 100= 2 x 10^4 since the answer is in kgs, we divide the number by 1000 20000/1000= 20 kgs