physics nlm

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prasadam123
prasadam123OP10mo ago
guys can u pls help without use of hyperbolic cosine
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Ricky
Ricky10mo ago
The string is in form of parabola y²=4ax. Radius of curvature at vertex of parabola is R=1/2a. You need to find the value of a.
prasadam123
prasadam123OP10mo ago
ayo what i didnt get
iTeachChem
iTeachChem10mo ago
parabola hai ACB is what he is saying. Have you studied parabolas? ( i dunno if it is or not I am going with what delu bhai is saying :D) that eqn you see y² = 4ax is of a parabola yo how do you type y²?
Ricky
Ricky10mo ago
I just long pressed 2 lol (Im on phone) My b,are you a neet student?
iTeachChem
iTeachChem10mo ago
haha nice he moved to 11th rn also why are they making you do tis for neet coaching?
BroGotNoQuotes
BroGotNoQuotes10mo ago
dang hes fast ((or bro skipped idk))
Comrade Rock Astley
When you derive a relation between forces you get a differential equation The result of that happens to have a cosh term So…it’s hard to avoid Here is how you balance the forces
Comrade Rock Astley
Physics Stack Exchange
Massive ropes and tension
Consider the diagram bellow, a massive string hanging in equilibrium My question is this: Can we take any 2 random point on the rope, say A and B and then use $\sum F=0$ on the rope between them: ...
prasadam123
prasadam123OP10mo ago
yes i understood that it is the equation of parabola but what am i to do with it sir i feel like we can use centre of mass? sir im doing this for myself(found this question somehwere) 😢 even this level is too much for neet? lmao nah i started this early prep in like august september already
BroGotNoQuotes
BroGotNoQuotes10mo ago
oh waw
Comrade Rock Astley
Go for it, if your method is logical and it works, then you might be able to use that as a general method
prasadam123
prasadam123OP10mo ago
wth i feel like neet is too easy-----i think the main difficulty comes in the competition and time management easy
iTeachChem
iTeachChem10mo ago
Tis true. Mad competition yea +solved @Comrade Rock Astley
iTeachChem Helper
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