Electric Feild and charge

Two balls of charges q, and q, initially have exactly same velocity. Both the balls are subjected to same uniform electric field for same time. As a result, the velocity of the first ball is reduced to half of its initial value and its direction changes by 60°. The direction of the velocity of second ball is found to change by 90°. The electric field and initial velocity of the charged particle are inclined at angle (1) 60° (2) 30° (3) 90° (4) +50°
No description
15 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user to close the thread when your doubt is solved. Mention the user who helped you solve the doubt. This will be added to their stats.
Deleted User
Deleted User10mo ago
@Gamertug mine is 120° and 135°
iTeachChem
iTeachChem10mo ago
hello! any attempt on this one?
Gamertug
GamertugOP10mo ago
no
iTeachChem
iTeachChem10mo ago
what are the ideas you can use to start this q? What equations can you form?
Cosmos
Cosmos10mo ago
hehe I did the same question yesterday Hint- the bodies will accelerate in the direction of the electric field
myst1cboomer
myst1cboomer10mo ago
impulse equation can be a good way to approach this
Gamertug
GamertugOP10mo ago
weird i was not getting any pings at all
myst1cboomer
myst1cboomer10mo ago
close the forum
Gamertug
GamertugOP10mo ago
ok , but question is still not solved
myst1cboomer
myst1cboomer10mo ago
@Gamertug same force same impulse same time
Gamertug
GamertugOP10mo ago
ok lemme try
iTeachChem
iTeachChem9mo ago
all g?

Did you find this page helpful?