Theo's Typesafe Cult•10mo ago

Playwright: How to check with considering URL Params

The thing is that my website redirects you to this URL: localhost:3000/home?cityId=... I want to just check if the first part is /home and ignore the url param. How can I do that with Playwright? Current code which not works:

await page.waitForURL("**/home");

expect(page.url()).toBe("http://localhost:3000/home");

await page.waitForURL("**/home");

expect(page.url()).toBe("http://localhost:3000/home");

Solution:

yeah, bro, nvm, thank you much for your help. I now did it like this.

await expect(page).toHaveURL(/^http:\/\/localhost:3000\/home(\?.*)?$/);

await expect(page).toHaveURL(/^http:\/\/localhost:3000\/home(\?.*)?$/);

...

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5 Replies

yanuu :)•10mo ago

you could use .toContainText(), according to docs

yanuu :)•10mo ago

https://playwright.dev/docs/test-assertions#non-retrying-assertions

Assertions | Playwright

Introduction

FleetAdmiralJakob 🗕 🗗 🗙OP•10mo ago

but not for the url right? This requires a locator to an element. I cannot use the toContainText() thing on urls

yanuu :)•10mo ago

page.url() returns a string, so i don't see why not honestly I don't know much about playwright, but from what I'm reading, .toContainText() should work fine so

expect(page.url()).toContainText("http://localhost:3000/home")

expect(page.url()).toContainText("http://localhost:3000/home")

Solution

FleetAdmiralJakob 🗕 🗗 🗙•10mo ago

yeah, bro, nvm, thank you much for your help. I now did it like this.

await expect(page).toHaveURL(/^http:\/\/localhost:3000\/home(\?.*)?$/);

await expect(page).toHaveURL(/^http:\/\/localhost:3000\/home(\?.*)?$/);

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Playwright: How to check with considering URL Params