❔ WPF ListView with LinkedList
Hello,
I have a ListView/GridView that is binded to a LinkedList. When I use the SelectedItem property of my ListView, it returns the value T of the LinkedListNode that is selected, and not the LinkedListNode itself, which is what I want. How do I get the LinkedListNode?
I could just use the Find() method on my LinkedList with the T value to get the node I want, but I would like to avoid this as it is a linear time operation.
Any help would be greatly appreciated!
7 Replies
I believe this wont work because the enumeration for a
LinkedList<T> goes over T and not LinkedListNode<T>Would making my own linked list class that implements IEnumerable work?
(with the enumerator returning the node instead of the T value)
Do you explicitly need the node?
Well not really, I'm trying to make a song playlist editor. A linked list would be good for adding/removing songs at any position in constant time, and for that i would need the node itself
I see. In that case you can make your own linked list that will enumerate over nodes instead of objects.
Yeah. I'll try to do that. Thanks for your help
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/close - otherwise I will mark this as stale and this post will be archived until there is new activity.