C#•17mo ago

❔ How to get a random enum value?

I have a function here where I would like to get a random value from an enum type. The goal is to give NextValue any enum type, and it will calculate its length and return a random value. The cast on return isn't working. Is this possible to do?

public static T NextValue<T>() where T : Enum
        {
            return (T)Rand.Next(0, Enum.GetNames(typeof(T)).Length - 1);
        }

public static T NextValue<T>() where T : Enum
        {
            return (T)Rand.Next(0, Enum.GetNames(typeof(T)).Length - 1);
        }

18 Replies

Aaron•17mo ago

you want GetValues, not GetNames

TheRanger•17mo ago

iirc its return (T)(object)Rand.Next

Aaron•17mo ago

and also that well, no okay

triplemochaOP•17mo ago

Appears to be working:

        public static T NextValue<T>() where T : Enum
        {
            return (T)(object)Rand.Next(0, Enum.GetValues(typeof(T)).Length - 1);
        }

        public static T NextValue<T>() where T : Enum
        {
            return (T)(object)Rand.Next(0, Enum.GetValues(typeof(T)).Length - 1);
        }

Aaron•17mo ago

public static T NextValue<T>() where T : struct
{
    var values = Enum.GetValues<T>();
    return values[Rand.Next(0, values.Length)];
}

public static T NextValue<T>() where T : struct
{
    var values = Enum.GetValues<T>();
    return values[Rand.Next(0, values.Length)];
}

that

triplemochaOP•17mo ago

I got this message:

Aaron•17mo ago

did you get the edit I made I swapped it from T : Enum to T : struct

triplemochaOP•17mo ago

I did.

TheRanger•17mo ago

remove the - 1 or ull never get the last value

Aaron•17mo ago

no that just doesn't work

enum E
{
    Value = 50
}

enum E
{
    Value = 50
}

triplemochaOP•17mo ago

Same thing. It's a custom Random class I made, so last value is max - 1.

TheRanger•17mo ago

this works for me

    public static T NextValue<T>() where T : Enum
    {
        var values = (T[])Enum.GetValues(typeof(T));
        return values[Random.Shared.Next(0, values.Length)];
    }

    public static T NextValue<T>() where T : Enum
    {
        var values = (T[])Enum.GetValues(typeof(T));
        return values[Random.Shared.Next(0, values.Length)];
    }

Aaron•17mo ago

ah okay make the constraint unmanaged, Enum

public static T NextValue<T>() where T : unmanaged, Enum
{
    var values = Enum.GetValues<T>();
    return values[Rand.Next(0, values.Length)];
}

public static T NextValue<T>() where T : unmanaged, Enum
{
    var values = Enum.GetValues<T>();
    return values[Rand.Next(0, values.Length)];
}

triplemochaOP•17mo ago

Seems to be working. Thanks! unmanaged is new to me.

Aaron•17mo ago

I think struct, Enum might also work? unmanaged just means there are no objects in it, which applies so enums, so that's what I'm used to using

TheRanger•17mo ago

works

triplemochaOP•17mo ago

Ah, I see.

Accord•17mo ago

Was this issue resolved? If so, run /close - otherwise I will mark this as stale and this post will be archived until there is new activity.

Gaming

Programming

❔ How to get a random enum value?