C#•13mo ago

✅ inputting list..

var size = int.Parse(Console.ReadLine());

            List<int> arr = new List<int>(size);
            for (int i = 0; i < size; i++)
            {
                arr[i] = int.Parse(Console.ReadLine());
            }

var size = int.Parse(Console.ReadLine());

            List<int> arr = new List<int>(size);
            for (int i = 0; i < size; i++)
            {
                arr[i] = int.Parse(Console.ReadLine());
            }

whats wrong with this code

13 Replies

ero•13mo ago

you tell us

wcasa•13mo ago

nukleer bomb•13mo ago

List<T> length is zero when created

Jimmacle•13mo ago

the capacity of a list is not the same as its size

nukleer bomb•13mo ago

That argument you are passing is capacity, not actual length

wcasa•13mo ago

List<int> arr = new List<int>(size); doesnt it say "create list with this size" ohhhh forgot those exist so i need to pushback them 1 by 1? is there more efficient solution? sounds slow..

nukleer bomb•13mo ago

it's already efficient if you keep parameter in constructor

wcasa•13mo ago

 var size = int.Parse(Console.ReadLine());

            List<int> arr = new List<int> { };
            for (int i = 0; i < size; i++)
            {

                int val = int.Parse(Console.ReadLine());
                arr.Add(val);
            }

 var size = int.Parse(Console.ReadLine());

            List<int> arr = new List<int> { };
            for (int i = 0; i < size; i++)
            {

                int val = int.Parse(Console.ReadLine());
                arr.Add(val);
            }

so thats the way?

nukleer bomb•13mo ago

It's efficient because List prepared some memory for size elements when constructor is called, but just didn't use it until Add is called

wcasa•13mo ago

so i should have that (size) at the end of the list?

nukleer bomb•13mo ago

You can drop it, but it will be less efficient

wcasa•13mo ago

okie thanks men! !close

Accord•13mo ago

Closed!

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✅ inputting list..